End of the rope! Match position

[Renman3000]

Hi,

It entirely depends on the value of “i_lastParticleIndex”, that’s why I asked how you are calculating it. But in general no, rope.solver.positions contains all particles managed by that solver, not just the particles for one particular rope. See:

http://obi.virtualmethodstudio.com/manua...cture.html
http://obi.virtualmethodstudio.com/manua...icles.html


Particle, Particle group and Attachment are 3 completely different things. If you mean how to get the position of the last particle in the rope, you can use this snippet I suggested before:

Code:

int lastParticleIndex = rope.elements[rope.elements.Count-1].particle2;
var position = rope.solver.transform.TransformPoint(rope.solver.positions[lastParticleIndex]);

If you're interested in particle groups instead, to get the index of a particle in a group you do:

Code:

var group= rope.blueprint.groups[groupIndex];
int particleIndex = rope.solverIndices[group.particleIndices[0]]; // in a rope, all groups contain a single particle.

Using this index you can look up its position in the solver.positions array as well.

Attachments have no position, since they're just a constraint relationship between a particle group and a transform.




Hi, so if you imagine a rope, with three particleAttachments, each with a unique particleGroup, where index 0 is left, index 1 is middle and index 2 is the right end of the rope. 

I want to know the position that is, index 2.