End of the rope! Match position

[josemendez]

Hi there, 
I have a rope. 

Is there a way to child a transform, renderer to the rope and specifuiclally a particle attachment so that this transform rednerer is always, whereever the selected particle attachment is, relative to its rope?

Basically, I would like a spehre to always be at the end of the rope.


Thanks

Hi,

There's many ways to do this, depending on what you want exactly.

If you want to make sure a transform is always at the position of the last particle in the rope, you can just set the position of the transform to the position of the last particle:

Code:

int lastParticle = rope.elements[rope.elements.Count-1].particle2;
transform.position = rope.solver.TransformPoint(rope.solver.positions[lastParticle]);

Another option is to retrieve the position of the last frame in the rope, which will provide you with orientation information as well. You do this by using

Code:

var frame = rope.GetComponent<ObiPathSmoother>().GetSectionAt(1); // normalized coord from 0/start to 1/end
transform.position = frame.position;
transform.rotation = Quaternion.LookRotation(frame.tangent, frame.binormal);

A third option is to use the utility ObiRopeAttach component, which implements the second option (GetSectionAt) so you don't have to write it yourself.


kind regards,